model 3 based on positive and negative exponent Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11

Which of the following numbers is not a factor of $5^p7^q$ (p ≠ 0, q ≠ 0)

a) 175

b) 735

c) 1225

d) 35

Answer:(b)

35 = 5 × 7

175 = 5 × 5 × 7

1225 = 5 × 5 × 7 × 7

735 = 5 × 7 × 7 × 3

Clearly, 735 is not a factor of $5^p7^q$

Question : 12

If $m^n$ = 169, what is the value of $(m+1)^(n - 1)$ ?

a) 13

b) 170

c) 196

d) 14

Answer:(d)

$m^n = 169 = 13^2$

m = 13, n = 2

$(m + 1)^{n - 1} = (13 + 1)^{2 - 1}$ = 14

Question : 13

If $27^{2x - 1} = (243)^3$ then the value of x is :

a) 6

b) 9

c) 7

d) 3

Answer:(d)

$27^{2x - 1} = (243)^3$

$(3^3)^{2x - 1} = (3^5)^3$

$(3)^{3{2x - 1}} = (3)^{5×3}$

3(2x - 1) = 5 × 3

or 2x - 1 = 5 ∴ x = 3

Question : 14 [SSC CGL Prelim 2000]

$(36)^{1/6}$ is equal to :

a) 6

b) $√^3{6}$

c) $√6$

d) 1

Answer:(b)

$(36)^{1/6}=(6^2)^{1/6}$

=$(6)^{2/6}=(6)^{1/3}=√^3{6}$

Question : 15 [SSC CHSL 2011]

If $2^x = 3^y = 6^{ - z}$ then $(1/x+1/y+1/z)$ is equal to

a) 1

b) - $1/2$

c) $3/2$

d) 0

Answer:(d)

$2^x = 3^y = 6^{ - z}$

$2^x = 3^y = 6^{ - z}=k$

$2=k^{1/x}; 3=k^{1/y}; 6=k^{-1/z}$

Since, 2×3=6

$k^{1/x}×k^{1/y}=k^{-1/z}$

$k^{1/x+1/y}=k^{-1/z}$

$1/x+1/y=-1/z⇒ 1/x+1/y+1/z=0$

IMPORTANT quantitative aptitude EXERCISES

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